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/* Test pthread_cond_clockwait timeout.
Copyright (C) 2019-2021 Free Software Foundation, Inc.
This file is part of the GNU C Library.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, see
<https://www.gnu.org/licenses/>. */
#include <errno.h>
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <sys/time.h>
#include <support/check.h>
#include <support/timespec.h>
#include <support/xthread.h>
static pthread_mutex_t mut = PTHREAD_ERRORCHECK_MUTEX_INITIALIZER_NP;
static pthread_cond_t cond = PTHREAD_COND_INITIALIZER;
static int
do_test_clock (clockid_t clockid)
{
/* Get the mutex. */
xpthread_mutex_lock (&mut);
/* Waiting for the condition will fail. But we want the timeout here. */
const struct timespec ts_now = xclock_now (clockid);
const struct timespec ts_timeout =
timespec_add (ts_now, make_timespec (0, 500000000));
/* In theory pthread_cond_clockwait could return zero here due to
spurious wakeup. However that can't happen without a signal or an
additional waiter. */
TEST_COMPARE (pthread_cond_clockwait (&cond, &mut, clockid, &ts_timeout),
ETIMEDOUT);
xpthread_mutex_unlock (&mut);
return 0;
}
static int
do_test (void)
{
do_test_clock (CLOCK_MONOTONIC);
do_test_clock (CLOCK_REALTIME);
return 0;
}
#include <support/test-driver.c>
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