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/* Test for memory handling in regex.
Copyright (C) 2001-2021 Free Software Foundation, Inc.
This file is part of the GNU C Library.
Contributed by Ulrich Drepper <drepper@redhat.com>, 2001.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, see
<https://www.gnu.org/licenses/>. */
#include <sys/types.h>
#include <mcheck.h>
#include <regex.h>
#include <stdio.h>
#include <stdlib.h>
static const char text[] = "This is a test; this is a test";
int
main (void)
{
regex_t re;
regmatch_t rm[2];
int n;
mtrace ();
n = regcomp (&re, "a test", REG_EXTENDED);
if (n != 0)
{
char buf[500];
regerror (n, &re, buf, sizeof (buf));
printf ("regcomp failed: %s\n", buf);
exit (1);
}
for (n = 0; n < 20; ++n)
regexec (&re, text, 2, rm, 0);
regfree (&re);
return 0;
}
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